// BISECTION METHOD IMPLEMENTATION IN JAVA // This program uses bisection method to solve for x^3 + 4x^2 -10 = 0 package nisarg; import java.The convergence is linear, slow but steady C Program implementing the Bisection Method ( Numerical Computing ) /*This program in C is used to demonstarte bisection method.The method involves repeatedly bisecting of the interval and ultimately reaching to the.Bisection method is based on the repeated application of the intermediate value property.It requires two initial guesses and is a closed bracket method.This method is used to find roots in a continuous function between two given interval, given the two values to be in the opposite signs..Here f (x) represents algebraic or transcendental equation.Given a function f (x) on floating number x and two numbers ‘a’ and ‘b’ such that f (a)*f (b) < 0 and f (x) is continuous in [a, b].Bisection Method C Program Output.In this method we are given a function f (x) and we approximate 2 roots a and b for the function such that f (a).For this, f(a) and f(b) should be of opposite nature i.Given a function f (x) on floating number x and two numbers ‘a’ and ‘b’ such that f (a)*f (b) < 0 and f (x) is continuous in [a, b].Scanner; public class BetterBisection { public static void main (String [] args) { double a, b, c; // a, b.Find root of function in interval [a, b] (Or find a value of x such that f (x) is 0).High = userinput, low = 0, mid (low + high) /2, problem is how to how to change values then Now I only need to tweak the f () method so that I can evaluate the f (a) , f (b) and f (c).This program implements Bisection Method for finding real root of nonlinear function in C++ programming language.Note: Bisection method guarantees write a program to implement bisection method in c the convergence of a function f(x) if it is continuous on the interval [a,b] (denoted by x1 and x2 in the above algorithm.Program 1: Bisection Method Write a Program to apply Bisection Method to solve non-linear equations.Please give me a sample of that how to make a generic code to find square-root.Description: Given a closed interval [a,b] on which f changes sign, we divide the interval in half and note that f must change sign on either the right or the left half (or be zero at the midpoint of [a,b].The method is based upon bisecting